由题可得,(1/tanα)+(1/tanβ)=m-1,(1/tanα)*(1/tanβ)=m,化简得,(tanα+tanβ)/(tanβ*tanα)=m-1,1/(tanβ*tanα)=m,则有：（1）当m≠0时,tanα+tanβ=(m-1)/m,tanβ*tanα=1/m,而tan(α+β)=(tanα+tanβ)/(1-ta...