已知:3^m-n-1=27,求多项式m^2+mn-2n^2-10m-2n+24
人气:300 ℃ 时间:2020-01-31 03:43:53
解答
27=3^3
所以m-n-1=3
m-n=4
原式=(m+2n)(m-n)-10m-2n+24
=4(m+2n)-10m-2n+24
=4m+8n-10m-2n+24
=-6m+6n+24
=-6(m-n)+24
=-24+24
=0
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