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b^3n-1 c^2/a^2n+1×a^2n-1/b^3n-2=
人气:116 ℃ 时间:2019-11-15 06:54:18
解答
b^(3n-1) c^2/a^(2n+1)×a^(2n-1)/b^(3n-2)
= a^[(2n-1)-(2n+1)]b^[(3n-1)-(3n-2)] c^2
= a^[2n-1-2n-1]b^[3n-1-3n+2] c^2
= a^[-2]b^[1] c^2
= a^(-2)b c^2
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