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计算:b^(3n-1)/a^(2n-1)×c÷b^(3n-2)/a^2n
人气:191 ℃ 时间:2019-12-19 01:19:27
解答
b^(3n-1)/a^(2n-1)×c÷b^(3n-2)/a^2n
=b^(3n-1)/a^(2n-1)×c×a^2n/b^(3n-2)
=bb^(3n-2)/a^(2n-1)×c×aa^(2n-1)/b^(3n-2)
=abc不好意思,题打错了b^(3n-1)/a^(2n+1)×c÷b^(3n-2)/a^2nb^(3n-1)/a^(2n+1)×c÷b^(3n-2)/a^2n=b^(3n-1)/a^(2n+1)×a^2n/b^(3n-2)×c=bb^(3n-2)/aa^2n×a^2n/b^(3n-2)×c=bc/a
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