h/sinαsinβ*根号下(sin∧α+sin∧β-2sinαsinβcosαcosβ-2sin∧αsin∧β)
这个.怎么化简啊~
人气:415 ℃ 时间:2020-02-05 10:54:57
解答
设α>β>0h/sinαsinβ*√(sin^α+sin^β-2sinαsinβcosαcosβ-2sin^αsin^β)=h/sinαsinβ*√(sin^α+sin^β-2sinαsinβcosαcosβ-sin^αsin^β-sin^αsin^β)=h/sinαsinβ*√(sin^α+sin^β-2sinαsin...
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