证明：当m为负数时（m+5）的平方-（m-9）的平方是28的倍数
人气：422 ℃ 时间：2020-04-12 13:49:44
解答
解
(m+5)^2-(m-9)^2
=[(m+5)-(m-9)][(m+5)+(m-9)]
=14×(2m-4)
=28(m-2)
∴m为负数时,是28的倍数
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