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1.分解因式:4x³-31x+15
2.把12x²+14xy-20y²+20x-11y+3
3.x³+6x²+11x+6
4.x⁴+2x³-9x²-2x+8
5.x²+xy-6y²+x+13y-6
6.x³+5x²+3x-9
人气:472 ℃ 时间:2020-05-06 16:59:16
解答
答:1.原式=(2x-5)(2x²+5x-3)=(2x-5)(2x-1)(x+3)2.原式=3.原式=(x+3)(x²+3x+2)=(x+3)(x+2)(x+1)4.原式=(x-2)(x³+4x²-x-4)=(x-2)(x+1)(x²+3x-4)=(x-2)(x+1)(x+4)(x-1)5.原式=6.原式=(x+3)(x...那1.(x-2)³-(y-2)³-(x-y)³=2.ab(a+b)²-(a+b)²+1=3.9x²-6x-y²+4y-3=4.(x²+5x+20(x²+5x+3)-12=5.a²-b²+4a+2b+36.(x+y)(x+y+2xy)+(xy+1)(xy-1)回复:哇塞,加量记得加价啊!1.原式=(x-2-y+2)[(x-2)²+(x-2)(y-2)+(y-2)²]-(x-y)(x-y)²=(x-y)[(x-2)²+(x-2)(y-2)+(y-2)²-(x-y)²]=(x-y)(x²-4x+4+xy-2x-2y+4+y²-4y+4-x²-y²+2xy)=(x-y)(-6x+3xy-6y+12)=3(x-y)(xy-2x-2y+4)=3(x-y)(x-2)(y-2)2.原式=3.原式=9x²-6x+1-y²+4y-4=(3x-1)²-(y-2)²=(3x-1+y-2)(3x-1-y+2)=(3x+y-3)(3x-y+1)4.原式=(x²+5x)²+5(x²+5x)+6-12=(x²+5x)²+5(x²+5x)-6=(x²+5x+6)(x²+5x-1)=(x+2)(x+3)(x²+5x-1)5.原式=a²+4a+4-b²+2b-1=(a+2)²-(b-1)²=(a+2+b-1)(a+2-b+1)=(a+b+1)(a-b+3)6.原式=
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