函数y=f(x)的定义域为R,对任意x,y∈R,都有f(x+y)=f(x)+f(y),f(xy)=f(x)f(y)恒成立,当x不等于y时,()
函数y=f(x)的定义域为R,对任意x,y∈R,都有f(x+y)=f(x)+f(y),f(xy)=f(x)f(y)恒成立,当x不等于y时,f(x)不等于f(y),证明1;若x>0,则f(x)>0; 2:f(x)是R上的单调递增函数.
人气:382 ℃ 时间:2019-10-29 10:38:11
解答
1.f(x+y)=f(x)+f(y)令y=0f(x)=f(x)+f(0)f(0)=0x≠0时,f(x)≠0对任意的x>0f(x)=f(√x*√x)=f(√x)*f(√x)>02.任取x1,x2,使x10f(x2-x1)>0f(x2)=f(x1)+f(x2-x1)>f(x1)∴f(x)是R上的单调递增函数...
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