> 数学 >
1/(2X3)+1/(3X4)+1/(4X5)+1/(5X6)+...+1/(100X101)=?
人气:267 ℃ 时间:2020-03-29 10:00:00
解答
=(1/2-1/3)+(1/3-1/4)+……+(1/100-1/101)
中间正负抵消
=1/2-1/101
=99/202
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版