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-2(x-y)^3+12(y-x)^2-18x+18y
人气:247 ℃ 时间:2020-10-02 03:15:30
解答
-2(x-y)^3+12(y-x)^2-18x+18y
=-2[(x-y)^3-6(x-y)^2+9(x-y)]
=-2(x-y)[(x-y)^2-6(x-y)+9]
=-2(x-y)(x-y-3)^2=-2(x-y)[(x-y)^2-6(x-y)+9]=-2(x-y)(x-y-3)^2
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