原方程变为96/x^=(2x-1)/(x+4)+(3x-1)/(x-4)-5=[(2x-1)(x-4)+(3x-1)(x+4)]/(x^-16)-52x^-9x+43x^+11x-4___________5x^+2x,又变为96/x^=(2x+80)/(x^-16),∴48(x^-16)=(x+40)x^,x^3-8x^+768=0,请检查题目...