若关于x,y的二元一次方程组3x+2y=m+1,4x+y=m,中的x,y均小于2,求m的值
人气:492 ℃ 时间:2019-10-17 04:51:43
解答
3x+2y=m+1 (1)
4x+y=m (2)
(1)-(2)*2 得
-5x=-m+1
x=(m-1)/5
y=m-4(m-1)/5=(m+4)/5
由于x,y均小于2
即:
(m-1)/5
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