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分解因式:2(3a²-b)-a(3b-4)
已知m²-3m+1=0,求m²+m²分之1
人气:445 ℃ 时间:2020-06-03 01:46:33
解答
3a^2-b)-a(3b-4)
=6a^2-2b-3ab+4a
=2a(3a+2)-b(3a+2)
=(2a-b)(3a+2)
m^2-3m+1=0,求m^2+1/m^2
m^2-3m+1=0
m-3+1/m=0
m^2+1/m^2=(m+1/m)^2-2=3^2-2=7
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