lim x趋近于无穷大 sin3次方x分之tanx-sinx的极限
人气:267 ℃ 时间:2019-11-01 14:11:11
解答
你确定是x趋于无穷么?应该是趋于0吧
注意tanx-sinx=tanx*(1-cosx)
在x趋于0的时候,sinx和tanx等价于x,而1-cosx等价于0.5x^2
所以
原极限
=lim(x趋于0) x^3 / (x* 0.5x^2)
=2
推荐
猜你喜欢
- Knowing what these elements are makes it possible to use them consciously
- .Whatever you can do,______.
- √2又1/12化简
- where is the supermarket?为什么加the不是加a
- ()(luck),they missed the last bus,so they had to take the taxi back home even it’s very
- 在梯形ABCD中,AD//BC,AB垂直AC.角B=45度,AD=根号2,BC=根号32,求DC的长
- a与b互为相反数,且|a-b|=1/5,那么a-ab+b/a^2+ab+1=
- for的用法:如so i'd like to ask for three days leave中for 的用法.例举其他.