求因式分解 (x+2)^3-1 (3a-b)(x-y)(a+3b)(x-y) (x+2)(x+4)+x^2-4 a^2b^2+2b_数学解答

求因式分解 (x+2)^3-1 (3a-b)(x-y)(a+3b)(x-y) (x+2)(x+4)+x^2-4 a^2b^2+2b-1

人气：162 ℃　时间：2019-09-02 09:45:51

解答

(x+2)^3-1=[﹙x＋2﹚－1][﹙x＋2﹚²＋﹙x＋2﹚＋1]=﹙x＋2－1﹚﹙x²＋4x＋4＋x＋2＋1﹚=﹙x＋1﹚﹙x²＋5x＋7﹚(3a-b)(x-y)＋(a+3b)(x-y) (是这个吗?)=(x-y)[(3a-b)＋(a+3b)]=(x-y)﹙4a＋2b﹚=2(x-y)...