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求y=x^3/(x-1)^2的斜渐近线
人气:150 ℃ 时间:2020-06-16 00:46:12
解答
定义域x-1≠0,x≠1垂直渐近线为x=1∵lim(x-->∞)[y-(x+2)]=lim(x-->∞)[x³-(x-1)²(x+2)]/(x-1)=lim(x-->∞)(3x-2)/(x²-2x+1)=lim(x-->∞)(3/x-2/x²)/(1-2/x+1/x²)=(0-0)/(1-0+0)=0又y-(x+2...
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