函数y=lg(3-4x+x2)的定义域为M,当x∈M时,则f(x)=2x+2-3×4x的最大值为______.
人气:468 ℃ 时间:2019-09-18 02:29:52
解答
函数y=lg(3-4x+x2)的定义域为M,∴3-4x+x2>0,即(x-1)(x-3)>0,解得M={x|x>3或x<1},∴f(x)=2x+2-3×4x,令2x=t,0<t<2或t>8,∴f(t)=-3t2+t+2=-3(t-16)2+2512,当t=16时,f(t)取最大值,f(x...
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