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(2+i)^3(4-2i)/5i(1+i)=1-7i 怎么算的求详细过程
人气:221 ℃ 时间:2020-03-25 08:30:08
解答
(2+i)³(4-2i)/5i(1+i)
=(8+3×4×i+3×2×i²+i³)(4-2i)/5(i-1)
=(8+12i-6-i)(4-2i)/5(i-1)
=2(2+11i)(2-i)(i+1)/5(i-1)(i+1)
=2(2+11i)(i+3)/5(-1-1)
=-(2+11i)(i+3)/5
=-(35i-5)/5
=1-7i
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