计算(4x^2-2x^3+6x)/(-2x)-(x-1)^2y^2-4/y^2-y-6)+(y+2/y-3)/(y+1/y-3)_数学解答

计算
(4x^2-2x^3+6x)/(-2x)-(x-1)^2
y^2-4/y^2-y-6)+(y+2/y-3)/(y+1/y-3)

人气：290 ℃　时间：2020-06-08 18:17:48

解答

原式=-2x+x^2-3-x^2+2x-1
=-4
原式=(y+2)(y-2)/(y-3)(y+2)+(y+2)/(y+1)
=(y-2)/(y-3)+(y+2)/(y+1)
=(y^2-y-2+y^2-y-6)/(y-3)(y+1)
=(2y^2-2y-8)/(y-3)(y+1)