已知方程x²+y²-2(m+3)x+2(1-4m)²y+16m的四次方+9=0表示一个圆
1.求实数m的取值范围
2.求该圆半径r的取值范围
3.求圆心的轨迹方程
第三问的
y=4m^2-1
=4*((m+3)^2-6m-9)-1
什么意思啊?
人气:113 ℃ 时间:2019-12-01 13:18:14
解答
X^2+Y^2-2(m+3)X+2(1-4m^2)Y+16m^4+9=0(X-(m+3))^2+(Y+1-4m^2)^2=(m+3)^2+(1-4m^2)^2-9-16m^4等式左边可以化为左=(m+3)^2+(1-4m^2)^2-9-16m^4=m^2+6m+9+1-8m^2+16m^4-9-16m^4=-7m^2+6m+11.左=-(7m+1)(m-1)>0=> -1/7...
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