(6x+2)/(x^2+3x+2)=5-(2x^2+6x+4)/(3x+1)2(3x+1)/(x^2+3x+2)+2(x^2+3x+2)/(3x+1)-5=0设(3x+1)/(x^2+3x+2)=y则2y+2/y-5=02y^2-5y+2=0(2y-1)(y-2)=0解得y=1/2或y=2则(3x+1)/(x^2+3x+2)=1/2或(3x+1)/(x^2+3x+2)=2即x^2+...