> 数学 >
若x=根号5-2,求x^3+4x^2-2x-2的值
人气:284 ℃ 时间:2020-05-31 23:37:23
解答
x^3+4x^2-2x-2
=x^3+4x^2+4x-6x-2
=x(x^2+4x+4)-6x-2
=x(x+2)^2-6x-2
=x(√5-2+2)^2-6x-2
=5x-6x-2
=-x-2
=-(√5-2)-2
=-√5+2-2
=-√5
推荐
猜你喜欢
© 2025 79432.Com All Rights Reserved.
电脑版|手机版