数学之美团为你解答f(x)=2sin(π-x)cosx+2cos^2x=2sinxcosx+2cos^2x=sin2x+1+cos2x(1) f(π/6)=sin(π/3)+cos(π/3)+1=sqrt(3)/2+1/2+1=(3+sqrt(3))/2(2) f(x)=sin2x+1+cos2x=sqrt(2)sin(2x+π/4)+1,所以函数的周期...