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x+3/x+2-2-x/x^2-4解分式 八下数学知识
人气:221 ℃ 时间:2020-03-22 01:50:52
解答
原式=(x+3)/(x+2)+(x-2)/(x+2)(x-2)
=(x+3)/(x+2)+1/(x+2)
=(x+3+1)/(x+2)
=(x+4)/(x+2)题输错了、、(x+3)/(x+2)+(2-x)/(x^2-4)原式=(x+3)/(x+2)-(x-2)/(x+2)(x-2) =(x+3)/(x+2)-1/(x+2) =(x+2)/(x+2) =1
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