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一物体做简谐振动,振动方程为x=Acos(wt+2/π),则该物体在t=0和t=T/8时时刻的动能之比?(T为周期)
人气:259 ℃ 时间:2019-12-07 14:05:43
解答
x=Acos(wt+2/π)?
x=Acos(wt+π/2)?不好意思啊,是π/2x=Acos(wt+π/2),v=w*Asin(wt+π/2),Ek=m(wA)^2*sin^2(wt+π/2)/2,
t=0,Ek=m(wA)^2*sin^2(w*0+π/2)/2=m(wA)^2/2,
t=T/8,w*T/8=π/4,Ek=m(wA)^2*sin^2(π/4+π/2)/2=m(wA)^2/4,
动能之比:1/2比1/4,或,2比1
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