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数学
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已知a=(cosh,sinh),b=(cosx,sinx)(0
人气:204 ℃ 时间:2019-12-21 11:51:53
解答
∵a=(cosh,sinh),b=(cosx,sinx).∴a+b=(cosh+cosx,sinh+sinx).a-b=(cosh-cosx,sinh-sinx).∴(a+b)*(a-b)=(cos²h-cos²x)+(sin²h-sin²x)=(cos²h+sin²h)-(cos²x+sin²x)=1-1=0....
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