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y=(sinx)^x,求dy/dx=?
人气:453 ℃ 时间:2020-04-15 09:28:03
解答
y=(sinx)^x=e^[x*ln(sinx)] y'={e^[x*ln(sinx)]}' ={e^[x*ln(sinx)]}*[x*ln(sinx)]' ={e^[x*ln(sinx)]}*[ln(sinx)+x*1/sinx*cosx] ={(sinx)^x}*[ln(sinx)+x*1/sinx*cosx]
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