[(2b/a^2-b^2)+(a/a^2+ab)]÷3/a-b
人气:431 ℃ 时间:2020-02-05 18:23:38
解答
[(2b/a^2-b^2)+(a/a^2+ab)]÷3/a-b
=[(2b/(a+b)(a-b)+a/a(a+b)]×(a-b)/3
=[(2b/(a+b)(a-b)+1/(a+b)]×(a-b)/3
=[(2b/(a+b)+(a-b)/(a+b)]×1/3
=(2b+a-b)/(a+b)×1/3
=(a+b)/(a+b)×1/3
=1/3
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