∫（2x-1）/√x dx
=∫2x/√x -1/√x dx
=∫2√x dx-∫1/√x dx/////////令t=√x
=2∫tdt^2-∫1/tdt^2
=2∫2t^2dt-∫2dt
=2*2/3t^3-2t+C
=4/3x^(3/2)-2x^(1/2)+C (C为任意常数)
或者写成4/3x√x-2√x+C