解关于x的不等式2ax^2-(2a+1)x+1＜0.
人气：126 ℃ 时间：2020-04-09 20:44:38
解答
2ax^2 - (2a +1)x +1 < 0 ==> (2ax - 1)(x -1) < 0(1) a = 0 -(x - 1) < 0 ==> x -1 > 0 ==> x >1(2) a > 1/2 (2ax - 1)(x -1) < 0 ==> 1/2a < x < 1(3) a =1/2 (2ax - 1)(x -1)(x - 1)^2 < 0 x 在实数范围...
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