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(n+1)(n+2)/1 +(n+2)(n+3)/1 +(n+3)(n+4)/1
人气:379 ℃ 时间:2020-04-05 14:25:19
解答
(n+1)(n+2)/1 +(n+2)(n+3)/1 +(n+3)(n+4)/1=(n+1)(n+2) +(n+2)(n+3) +(n+3)(n+4)=(n+2)(n+1+n+3)+n^2+7n+12=(n+2)(2n+4)+n^2+7n+12=2(n+2)^2+n^2+7n+12=2(n^2+4n+4)+n^2+7n+12=3n^2+15n+20
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