已知a^3x=3,b^3y=2,求(ax^2x * b^2y)^3-(a^4y)^3+(-b^y)^3
人气:172 ℃ 时间:2020-04-28 07:56:43
解答
(a^2x * b^2y)^3-(a^4y)^3+(-b^y)^3
=(a^6x*b^6y)-(a^12y)-(b^3y)
=(a^3x*b^3y)^2-(a^3y)^4-(b^3y)
=(3*2)^2-2^4-2
=36-16-2
=20-2
=18
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