> 数学 >
行列式求根,x-1 1 2 1 x-5 0 =0的三个根是什么 2 0 x-5
人气:444 ℃ 时间:2020-07-22 15:17:32
解答
x-1 1 2
1 x-5 0
2 0 x-5
r3-2r2
x-1 1 2
1 x-5 0
0 -2(x-5) x-5
c2+2c3
x-1 5 2
1 x-5 0
0 0 x-5
= (x-5)[(x-1)(x-5)-5]
= (x-5)(x^2-6x)
= x(x-5)(x-6).
推荐
猜你喜欢
© 2026 79432.Com All Rights Reserved.
电脑版|手机版