化简[sin(π/2-α）cos(π/2-α)]/cos(π+α)-[sin(π-α)cos(π/2-α)]/sin(π+α)_数学解答 - 作业小助手

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化简[sin(π/2-α）cos(π/2-α)]/cos(π+α)-[sin(π-α)cos(π/2-α)]/sin(π+α)

人气：294 ℃　时间：2020-04-07 14:00:00

解答

原式=(cosαsinα)/(-cosα)-(sinαsinα)/sinα
=-sinα-sinα
=-2sinα

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