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sin(x+π/3)+2sin(x-π/3)-根号3cos(2π/3-x)
求化简过程.
人气:195 ℃ 时间:2019-10-25 15:39:22
解答
原式=sin(x+π/3)+√3cos(x+π/3)+2sin(x-π/3)=2[1/2sin(x+π/3)+√3/2cos(x+π/3)]+2sin(x-π/3)=2sin(x+π/3+π/6)+2sin(x-π/3)=2[sin(x+π/2)+sin(x-π/3)]=2(cosx+√3/2sinx-1/2cosx)=2(√3/2sinx+1/2co...
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