f(x)=x^4+ax^3+2x^2+bf’(x)=4x^3+3ax^2+4x=x(4x^2+3ax+4)把里面的函数拿出来看4x^2+3ax+4的△=9a^2-64a∈[-2,2]时,△=9a^2-640∴f(x)在[-2,0]单调递减在[0,2]单调递增f(x)max是f(-2)或f(2)f(-2)≤1f(2)≤1b≤-8a-23...我写错了，是f(x)≤1在[-1,1]上恒成立。f(x)在[-1,0]单调递减在[0,1]单调递增f(x)max是f(-1)或f(1)f(-1)≤1f(1)≤1b≤a-2①b≤-2-a②∵对于任意a均成立b≤-4