已知二次函数y=-x²+x-1/5,当自变量取m时,对应的函数值大于0,当自变量x分别取m-1,m+1时对应的函数值y1,y2,则y1,y2必须满足_y1+y2＞0____(y1+y2)/2=-m²+m-1/5＞0;∴y1+y2＞0;很高兴为您解答,skyhunter002为...