cos（2x-π/6)=cos2(x-π/12)而sin（2x-π/3)=cos[π/2-(2x-π/3)]=cos(π/2-2x+π/3)=cos(2x-5π/6)=cos2(x-5π/12)=cos2(x-π/12-π/3)要移动得到cos2(x-π/12),根据左加右减得所以向__左__移,移__ π/3 _单位...