f(x)=2（sin2x+√3/2）cosx-sin3x
=2sin2xcosx+√3cosx-sin3x
=sin3x+sinx+√3cosx-sin3x
=2sin(x+π/3)
x的最小值为2.最大值为-2
∴x+π/3=2kπ+π/2,k∈Z,
x=2kπ+π/6,k∈Z,f(x)max=2
x+π/3=2kπ-π/2,
x=2kπ-5π/6,k∈Z,f(x)min=-2
f（x）=根号3
第二问.2sin(x+π/3) = 根号3
sin(x+π/3) =根号3/2
sin(π/3)=sin(2π/3)=根号3/2
因为x属于（0,派）
所以x=π/3