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f(x)=2(sin2x+根号3/2)cosx-sin3x 求函数最大值和最小值.考试.
人气:289 ℃ 时间:2019-10-06 23:29:54
解答
f(x)=2(sin2x+√3/2)cosx-sin3x=2sin2xcosx+√3cosx-sin3x=sin3x+sinx+√3cosx-sin3x=2sin(x+π/3)∴x+π/3=2kπ+π/2,k∈Z, x=2kπ+π/6,k∈Z,f(x)max=2x+π/3=2kπ-π/2,x=2kπ-5π/6,k∈Z,f(x)min=-2...
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