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计算a+[a+b]+[a+2b]+[a+3b]+...+[a+99b]
人气:452 ℃ 时间:2020-04-13 20:15:24
解答
=a+[a+b]+[a+2b]+[a+3b]+...+[a+99b]
=100a+b+2b+3b+...+99b
=100a+(1+2+3+..+99)*b
=100a+99*(1+99)/2 *b
=100a+4950b
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