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数学
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求cos2x\(cosx+sinx)的不定积分?
请前辈门写清楚解题的步骤,谢谢!
人气:109 ℃ 时间:2019-11-16 16:24:32
解答
∫cos2x/(cosx+sinx)dx
=∫[(cosx)^2-(sinx)^2]/(cosx+sinx)dx
=∫cosx-sinx dx
=∫cosxdx-∫sinxdx
=sinx-(-cosx)+C
=sinx+cosx+C
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