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∫π/2 0 (cos2x/cosx+sinx)dx 的定积分
人气:402 ℃ 时间:2019-08-26 07:36:19
解答
∫π/2 0 (cos2x/cosx+sinx)dx
=∫π/2 0 (cos²x-sin²x)/(cosx+sinx)dx
=∫π/2 0 (cosx-sinx)dx
=sinx+cosx π/2 0
=(1+0)-(0+1)
=0
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