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数学
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(2a^2-3a+1)/(1-a^2)÷(4a^2-4a+1)/(2a^2+a-1)
人气:435 ℃ 时间:2020-04-26 20:35:13
解答
(2a^2-3a+1)/(1-a^2)÷(4a^2-4a+1)/(2a^2+a-1)
=[(2a-1)(a-1)/(1-a)(1+a)]×[(2a-1)(a+1)/(2a-1)²]
=-[(2a-1)/(1+a)]×[(a+1)/(2a-1)]
=-1
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