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已知x²-2x-2=0,求代数式(x-1)²+(x+3)(x-3)+(x-3)(x-1)的值
人气:496 ℃ 时间:2019-08-30 12:26:46
解答
(x-1)²+(x+3)(x-3)+(x-3)(x-1)
=x²-2x+1+x²-9+x²-4x+3
=3x²-6x-5
=3x²-6x-6+1
=3(x²-2x-2)+1 x²-2x-2=0
=1
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