设A为4阶方阵,A*为A的伴随矩阵,若|A|=3,则|A*|=?,|2A*|=?
人气:204 ℃ 时间:2020-01-24 16:52:07
解答
主要考察了公式:│A*│=│A│^(n-1)
证明:A*=|A|A^(-1)
│A*│=|│A│*A^(-1)|
│A*│=│A│^(n)*|A^(-1)|
│A*│=│A│^(n)*|A|^(-1)
│A*│=│A│^(n-1)
所以|A*|=3^3=27,|2A*|=6^3=216
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