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数学
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∫(cosx/sinx+cosx)dx 这个怎么算
人气:386 ℃ 时间:2020-01-26 08:34:40
解答
A=∫cosx/(sinx+cosx)dx
B=∫sinx/(sinx+cosx)dx
A+B=∫(cosx+sinx)/(sinx+cosx)dx =∫dx =x+c (1)
A-B=∫(cosx-sinx)/(sinx+cosx)dx =∫(d(cosx+sinx)/(sinx+cosx)=ln(cosx+sinx)+c (2)
[(1)+(2)]/2得:
A=∫cosx/(sinx+cosx)dx =x/2+1/2*ln(cosx+sinx)+c
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