|x²+1-m|＜3﹣3＜x²+1-m＜3m-4＜x²＜m+2∵A =[﹣1,2]⊆ B ∴2∈B,0∈B∴m+2＞2²且m-4＜0即m∈﹙2,4﹚,∴﹣√﹙m+2﹚＜x＜√﹙m+2﹚∴﹣√﹙m+2﹚＜﹣1且√﹙m+2﹚＞2∴m＞﹣1且m＞2即m＞2...