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x的2次方-4分之x-6-2x-x的2次方分之2
人气:353 ℃ 时间:2020-03-25 09:27:08
解答
(x-6)/(x^2-4)-2/(2x-x)^2
=(x-6)/[(X-2)(x+2)]-2/[x(2-x)]^2
=(x-6)/[(X-2)(x+2)]-2/[x(x-2)]^2
=[1/(x-2)][(x-6)/(x+2)-2/x(x-2)]
=[1/(x-2)][(x-6)x(x-2)-2(x+2)]/[(x-2)x(x+2)]
=(x^3-8x^2+10x-4)/[(x-2)^2x(x+2)].
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