(1)∵c=√3asinC-ccosA根据正弦定理a=2RsinA,b=2RsinB,c=2RsinC,∴sinC=√3sinAsinC√-sinCcosA∵sinC>0,约去得：√3sinA-cosA=1 两边除以2√3/2*sinA-1/2*cosA=1/2∴sin(A-π/6)=1/2∵A-π/6∈(-π/6,5π/6)∴A-π/...